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Fix unresolved reference in generated type parameter

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This commit is contained in:
Iaroslav Postovalov 2021-05-21 20:08:17 +07:00
parent bb228e0c68
commit 189449f40e
2 changed files with 6 additions and 6 deletions
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4
kmath-ast/src/jvmMain/kotlin/space/kscience/kmath/asm/internal/AsmBuilder.kt
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@ -342,8 +342,8 @@ internal class AsmBuilder<T>(
val MAP_INTRINSICS_TYPE: Type by lazy { getObjectType("space/kscience/kmath/asm/internal/MapIntrinsics") }
/**
* ASM Type for [space.kscience.kmath.misc.Symbol].
* ASM Type for [space.kscience.kmath.expressions.Symbol].
*/
val SYMBOL_TYPE: Type by lazy { getObjectType("space/kscience/kmath/misc/Symbol") }
val SYMBOL_TYPE: Type by lazy { getObjectType("space/kscience/kmath/expressions/Symbol") }
}
}

8
kmath-core/src/commonMain/kotlin/space/kscience/kmath/expressions/Symbol.kt
View File

@ -12,13 +12,13 @@ import kotlin.properties.ReadOnlyProperty
* A marker interface for a symbol. A symbol must have an identity.
* Ic
*/
public interface Symbol: MST {
public interface Symbol : MST {
/**
* Identity object for the symbol. Two symbols with the same identity are considered to be the same symbol.
*/
public val identity: String
public companion object{
public companion object {
public val x: StringSymbol = StringSymbol("x")
public val y: StringSymbol = StringSymbol("y")
public val z: StringSymbol = StringSymbol("z")
@ -48,7 +48,7 @@ public operator fun <T> Map<String, T>.get(symbol: Symbol): T? = get(symbol.iden
/**
* Set a value of [String]-keyed map by a [Symbol]
*/
public operator fun <T> MutableMap<String, T>.set(symbol: Symbol, value: T){
public operator fun <T> MutableMap<String, T>.set(symbol: Symbol, value: T) {
set(symbol.identity, value)
}
@ -60,6 +60,6 @@ public operator fun <T> Map<Symbol, T>.get(string: String): T? = get(StringSymbo
/**
* Set a value of [String]-keyed map by a [Symbol]
*/
public operator fun <T> MutableMap<Symbol, T>.set(string: String, value: T){
public operator fun <T> MutableMap<Symbol, T>.set(string: String, value: T) {
set(StringSymbol(string), value)
}